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Home/ Questions/Q 288365
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T05:48:33+00:00 2026-05-12T05:48:33+00:00

I’d have to say I’m no expert on using the STL. Here’s my problem,

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I’d have to say I’m no expert on using the STL. Here’s my problem, I have a class Called LdapClientManager which maintains a number of LDAP clients that are managed by ID. The container holding the LdapClients is declared as a member variable i.e.

typedef std::map<int, LdapClient *> LdapClientMap;
LdapClientMap _ldapClientMap;

The following function fails to compile with the error:

LdapClient * LdapClientManager::getLdapClient(unsigned int templateID)
{
    // Do we have an LdapClient
    LdapClientMap::const_iterator it = _ldapClientMap.find(templateID);
    if (it == std::map::end) {
        // no existing client, lets create it
        LdapClient * ldapClient = new LdapClient();
        if (ldapClient == NULL) {
            // TODO: handle out of memory condition
        }

        _ldapClientMap[templateID] = ldapClient;
        return ldapClient;
    }

    return it->second;
}

Unfortunately I get the following error at compile time, what does it mean. I haven’t found a solution in google as yet.

LdapClientManager.cc: In member function LdapClient*
LdapClientManager::getLdapClient(unsigned int)':
LdapClientManager.cc:33:
template class std::map’ used without template parameters

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T05:48:34+00:00Added an answer on May 12, 2026 at 5:48 am

    Replace std::map::end with _ldapClientMap.end().
    Also, new never returns 0, it throws an exception if the allocation fails.

    Note that the program can be made much shorter.

    LdapClient * LdapClientManager::getLdapClient(unsigned int templateID)
    {
        LdapClient *& value = _ldapClientMap[templateID];
        if (value == 0)
            value = new LdapClient();
        return value;
    }
    
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