Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 616383
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T18:19:17+00:00 2026-05-13T18:19:17+00:00

I’d like my Jython servlet to implement the HttpServlet.contextInitialized method but I’m not sure

  • 0

I’d like my Jython servlet to implement the HttpServlet.contextInitialized method but I’m not sure how to express this in the web.xml. What I currently have is:

from javax.servlet import ServletContextListener;
from javax.servlet.http import HttpServlet

class JythonServlet1 ( HttpServlet, ServletContextListener ):

        def contextInitialized( self, event ):
            print "contextInitialized"

            context = event.getServletContext()

        def contextDestroyed( self, event ):
            print "contextDestroyed"

            context = event.getServletContext()

        def doGet( self, request, response ):
            print "doGet"

        def doPost( self, request, response ):
            print "doPost"

And my web.xml looks like this:

<?xml version="1.0" encoding="UTF-8"?>
<web-app
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns="http://java.sun.com/xml/ns/javaee" 
    xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" 
    id="WebApp_ID" version="2.5">

  <display-name>JythonTest</display-name>

    <servlet>
        <servlet-name>PyServlet</servlet-name>
        <servlet-class>org.python.util.PyServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>PyServlet</servlet-name>
        <url-pattern>*.py</url-pattern>
    </servlet-mapping>

    <servlet>
        <description></description>
        <display-name>JythonServlet1</display-name>
        <servlet-name>JythonServlet1</servlet-name>
        <servlet-class>JythonServlet1</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

</web-app>

As you can see, in the last <servlet> entry I’d like to initialize the servlet with the context (where I can start a scheduler) but it doesn’t seem to work the same as with a Java servlet.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T18:19:18+00:00Added an answer on May 13, 2026 at 6:19 pm

    I don’t do Jython, but there’s no means of contextInitialized or contextDestroyed methods in the HttpServlet API. You’re probably looking for ServletContextListener interface which is normally to be implemented as the following Java-based example:

    package com.example;
    
    import javax.servlet.ServletContextListener;
    
    public class MyServletContextListener implements ServletContextListener {
        public void contextInitialized(ServletContextEvent event) {
            // ...
        }
        public void contextDestroyed(ServletContextEvent event) {
            // ...
        }
    }
    

    …which is to be definied as <listener> in web.xml as follows:

    <listener>
        <listener-class>com.example.MyServletContextListener</listener-class>
    </listener>
    

    This must give you an idea how to pickup it using Jython.

    You can optionally also let your servlet both extend HttpServlet and implement ServletContextListener like follows:

    public class MyServlet extends HttpServlet implements ServletContextListener {
        // ...
    }
    

    so that you can end up with the code you’ve posted (don’t forget to import the particular interface and define your class as both servlet and listener in web.xml). But this is not always considered a good practice.

    That said, you should be placing classes in a package to avoid portability problems. It may work in some environments, but not in other. Sun also discourages using packageless classes in non-prototyping environments. They can normally namely not be imported by other classes which are itself in a package.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 410k
  • Answers 410k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer Try using a regular Binding with a RelativeSource of TemplatedParent:… May 15, 2026 at 7:21 am
  • Editorial Team
    Editorial Team added an answer You need to duplicate the in-memory object because variable names… May 15, 2026 at 7:21 am
  • Editorial Team
    Editorial Team added an answer The cleanest way to do this would be to create… May 15, 2026 at 7:21 am

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.