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Home/ Questions/Q 4273830
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T07:45:55+00:00 2026-05-21T07:45:55+00:00

I’d like some sorthand for this: Map rowToMap(row) { def rowMap = [:]; row.columns.each{

  • 0

I’d like some sorthand for this:

Map rowToMap(row) {
    def rowMap = [:];
    row.columns.each{ rowMap[it.name] = it.val }
    return rowMap;
}

given the way the GDK stuff is, I’d expect to be able to do something like:

Map rowToMap(row) {
    row.columns.collectMap{ [it.name,it.val] }
}

but I haven’t seen anything in the docs… am I missing something? or am I just way too lazy?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T07:45:56+00:00Added an answer on May 21, 2026 at 7:45 am

    I’ve recently came across the need to do exactly that: converting a list into a map. This question was posted before Groovy version 1.7.9 came out, so the method collectEntries didn’t exist yet. It works exactly as the collectMap method that was proposed:

    Map rowToMap(row) {
        row.columns.collectEntries{[it.name, it.val]}
    }
    

    If for some reason you are stuck with an older Groovy version, the inject method can also be used (as proposed here). This is a slightly modified version that takes only one expression inside the closure (just for the sake of character saving!):

    Map rowToMap(row) {
        row.columns.inject([:]) {map, col -> map << [(col.name): col.val]}
    }
    

    The + operator can also be used instead of the <<.

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