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Home/ Questions/Q 583559
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:48:20+00:00 2026-05-13T14:48:20+00:00

I’d like to add a label to a wicket panel where the label’s model

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I’d like to add a label to a wicket panel where the label’s model is an enum value. Based on the value of that enum, I’d like to display a different message pulled from the page’s properties file.

For example, here’s an enum:

public enum ApprovalType { UNAPPROVED, APPROVED, BLOCKED };

I can easily add a label to the panel that has this enum as its model:

add(new Label("approval", new Model(ApprovalType.APPROVED)));

However, this will simply output UNAPPROVED, APPROVED, or BLOCKED. I’d like to output a localized message that is selected based on the value of this enum.

So if I have this properties file, what’s the best way to get these messages to output?

UNAPPROVED=Your membership is currently pending approval
APPROVED=Your membership has been approved
BLOCKED=You have been blocked from membership

I can get it working like this:

add(new Label("approval", new ResourceModel(ApprovalType.APPROVED.name());

But the problem is that ResourceModel only accepts a string (resource key). I’d like to pull the value of the resource key automatically from a model (preferrably a CompoundPropertyModel). In other words, I don’t want to do this:

Member member = (Member) getDefaultModelObject();
add(new Label("approval", new ResourceModel(member.getApproval().name())));

I’d rather do something like:

add(new EnumLabel("approval");  // assuming I have a CompoundPropertyModel

Is there a component that does this that comes with Wicket? Or do I need to write my own?

Lastly, I discovered this also works:

add(new Label("approval", new StringResourceModel(
    "${}", 
    new PropertyModel<ApprovalType>(getDefaultModel(),"approval")
)));

But this seems overly verbose, and still doesn’t utilize the simplicity of using CompoundPropertyModel.

Ideas?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T14:48:21+00:00Added an answer on May 13, 2026 at 2:48 pm

    Not sure if this ‘ll work, but maybe you could try writing your own EnumModel class that takes the value of an Enum and returns a ResourceModel value..

    Please say so if the above isn’t clear enough, I’ll try to elaborate.

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