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Home/ Questions/Q 7007495
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T21:36:52+00:00 2026-05-27T21:36:52+00:00

I’d like to create a regular expression in Python that will match against a

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I’d like to create a regular expression in Python that will match against a line in Python source code and return a list of function calls.

The typical line would look like this:

something = a.b.method(time.time(), var=1) + q.y(x.m())

and the result should be:

["a.b.method()", "time.time()", "q.y()", "x.m()"]

I have two problems here:

  1. creating the correct pattern
  2. the catch groups are overlapping

thank you for help

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T21:36:53+00:00Added an answer on May 27, 2026 at 9:36 pm

    I don’t think regular expressions is the best approach here. Consider the ast module instead, for example:

    class ParseCall(ast.NodeVisitor):
        def __init__(self):
            self.ls = []
        def visit_Attribute(self, node):
            ast.NodeVisitor.generic_visit(self, node)
            self.ls.append(node.attr)
        def visit_Name(self, node):
            self.ls.append(node.id)
    
    
    class FindFuncs(ast.NodeVisitor):
        def visit_Call(self, node):
            p = ParseCall()
            p.visit(node.func)
            print ".".join(p.ls)
            ast.NodeVisitor.generic_visit(self, node)
    
    
    code = 'something = a.b.method(foo() + xtime.time(), var=1) + q.y(x.m())'
    tree = ast.parse(code)
    FindFuncs().visit(tree)
    

    result

    a.b.method
    foo
    xtime.time
    q.y
    x.m
    
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