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Asked: 2026-05-14T18:51:48+00:00

I’d like to define a method accepting varargs, so that I get the types

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I’d like to define a method accepting varargs, so that I get the types with which it was called even in the case of nulls.

def foo(args: Any*) = ....

val s: String = null

foo(1, s) // i'd like to be able to tell in foo that args(0) is Int, args(1) is String
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1 Answer

  1. Editorial Team

    In terms of the original question, I’m pretty sure it’s not possible.

    Without knowing exactly what you’re trying to achieve (ie, why it must be a variable-length list of arbitrary types), it is difficult to offer an alternative. However, there are two things that came to my mind when I read the question that may be an option for you: Default argument values in combination with named arguments (requires Scala 2.8+), and the HList data type (less likely).

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