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Home/ Questions/Q 7904265
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T09:58:44+00:00 2026-06-03T09:58:44+00:00

I’d like to define a pointer type that is shared between device and host

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I’d like to define a pointer type that is shared between device and host code and internally stores the device and host pointer to the shared memory. I want it to determine at compile time, which pointer to actually return:

#define F inline __host__ __device__

class SharedMemory;
/**
 * 
 * Can only be set by allocating shared memory.
 */
template<typename T>
class SharedMemoryPtr {
public:
    SharedMemoryPtr() : hptr(0), dptr(0) {}

    //F ~ SharedMemoryPtr() {cudaFreeHost(hptr);} // Should be freed explicitly (?)

    // TODO: Don't allow copying/overwriting (at least not without freeing memory...)

    F T& operator() () {
#ifdef __CUDACC__
        return *dptr;
#else
        return *hptr;
#endif
    };

    F T* operator-> () {
#ifdef __CUDACC__
        return dptr;
#else
        return hptr;
#endif
    };

    F T& operator * () {
#ifdef __CUDACC__
        return *dptr;
#else
        return *hptr;
#endif
    };

    F T& operator[] (__int64 i) const {
#ifdef __CUDACC__
        return *(dptr + i);
#else
        return *(hptr + i);
#endif
    };

    friend SharedMemory;

    // TODO: Make obsolete (possible?)

    T * getHptr() {return hptr;} 
    T * getDptr() {return dptr;}

private:

    T *hptr, *dptr;
};

class SharedMemory {
public:
    template<typename T>
    static SharedMemoryPtr<T> allocate(int count = 1) {
        assert(count > 0);

        SharedMemoryPtr<T> sptr;

        cutilSafeCall(
            cudaHostAlloc(&sptr.hptr, sizeof(T) * count, cudaHostAllocMapped));
        assert(sptr.hptr);
        cutilSafeCall(
            cudaHostGetDevicePointer(&sptr.dptr, sptr.hptr, 0));
        assert(sptr.dptr);

        return sptr;
    }
};

This works fine as long as I use these pointers in code that is either in a cpp file (where __CUDACC__ is never defined) or a .h file (where __CUDACC__ is only defined if the function is used by some function in a cu file). However in a __host__ function in a .cu file, I get the devptr. Obviously, .cu files are processed exclusively by nvcc. Is there some other preprocessor macro that is defined ONLY for __global__ and __device__ functions, not just everything nvcc happens to process? Or do I need to separate my code?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T09:58:46+00:00Added an answer on June 3, 2026 at 9:58 am

    __CUDA_ARCH__ is actual only for device code. You can specify device code behavior with it.
    This macro actually get compute capability of device code (like 200 for 2.0.)

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