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Home/ Questions/Q 8066657
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T12:04:42+00:00 2026-06-05T12:04:42+00:00

I’d like to fire some code whenever a page is shown in the browser:

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I’d like to fire some code whenever a page is shown in the browser:

$(function() {
   console.log('got ready event!');
});

This event gets fired only when the browser downloads the page. If I navigate to a different page, then go back, the above snippet won’t be fired. It seems that the browser caches the page state, because the server does not receive any requests when the page is shown.
So when I go back to the page, it restores the cached page state without firing the ready event.

Is there an event I can listen to whenever the page is shown, regardless of whether the page is cached or not?

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  1. Editorial Team
    Editorial Team
    2026-06-05T12:04:43+00:00Added an answer on June 5, 2026 at 12:04 pm

    The directive cashe-control:no-cashe indicates cached information should not be used and instead requests should be forwarded to the origin server.

    <meta http-equiv="cashe-control" content="no-cashe">
    

    Try the pageshow event:

    This event works the same as the load event, except that it fires every time the page is loaded. The first time the page loads, the pageshow event fires just after the firing of the load event. The pageshow event uses a boolean property called persisted that is set to false on the initial load. It is set to true if it is not the initial load (in other words, it is set to true when the page is cached).

    $(document).bind('pageshow', function(){
       // ...
    })
    
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