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Editorial Team
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Asked: 2026-06-01T07:58:30+00:00

I’d like to format an integer in a way that it has leading zeros

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I’d like to format an integer in a way that it has leading zeros and thousand separators at the same time.

I know that someInt.ToString("D6"); will give me leading zeros, but apparently it doesn’t allow NumberGroupSeparator. On the other hand someInt.ToString("N"); will give me separators but no leading zeros…

Is it possible to combine both to print 123456 as 00 123 456? I know I can get string created with N and then manually add zeros to string in a loop or something, but maybe there’s better way?

EDIT:
Number of padding zeros (total digits length of number) should be adjustable.

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1 Answer

  1. Editorial Team

    If you want 00 123 456, just do:

    123456.ToString("00 000 000")

    If you need a fixed amount of zero’s, all I can think of is this:

    int NUM_LENGTH = 6;

//This is not very elegant
var NUM_STR = String.Join("", Enumerable.Range(0, NUM_LENGTH).Select((x, i) => (NUM_LENGTH - i) % 3 == 0 ? " 0" : "0"));

//But at least it works:
var example1 = 123456.ToString(NUM_STR); //Outputs  123 456
var example2 = 1234.ToString(NUM_STR); //Outputs 001 234
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