Question

I’d like to know how many element I have between two pointers to a tab, with a function.

For example in this code, nb would be 20.

int main(void)
{
  int t[50] = {0};
  int nb;

  nb = finding_number_element(&t[10], &t[30]);
  return (0);
}

Have you got a idea?

Answer 1

Try

int finding_number_element(int *a, int *b) 
{
  return (b - a);
}

if a and b will be pointers to the same array this should work.