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Home/ Questions/Q 8459711
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T13:24:19+00:00 2026-06-10T13:24:19+00:00

I’d like to know the most efficient way to count array elements whose value

  • 0

I’d like to know the most efficient way to count array elements whose value is set True.

This is my attempt but the code gets kind of long. I’m wondering if there is a built-in function for it already or could be done in a smarter way. In this case, I’d like to know the number of elements having true in $arr[‘key’][uniquekeyname][‘check’].

$arr = array();
$arr['keys'] = array(
    'a' => array('check' => true,  'otherinfo' => 'some data'),
    'b' => array('check' => false, 'otherinfo' => 'some data'),
    'c' => array('check' => false, 'otherinfo' => 'some data'),
    'd' => array('check' => true,  'otherinfo' => 'some data'),
);

$numChecked = 0;
foreach($arr['keys'] as $key) {
    if ($key['check']) 
        $numChecked++;          
}

echo $numChecked;
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T13:24:21+00:00Added an answer on June 10, 2026 at 1:24 pm

    The complexity will be O(n), so looping through it is just fine.

    I note that maybe you want to use the triple-equal operator === in order to compare the elements of your array to true, since having the field check set to another value will be counted right as it is now or with ==.

     'b' => array('check' => 150, 'otherinfo' => 'some data'),
    

    Will output:

     3
    

    Whereas:

    $numChecked = 0;
    foreach($arr['keys'] as $key) {
        if ($key['check'] === true) 
            $numChecked++;          
    }
    
    echo $numChecked;
    

    will get you

    2
    

    Maybe it is fine for your needs to get ==, assuming your array will always carry only true/false values.

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