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Home/ Questions/Q 7045507
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T02:32:20+00:00 2026-05-28T02:32:20+00:00

I’d like to multiply a random number vector PT(n)=rand(1,n) by a matrix M(mxn) but

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I’d like to multiply a random number vector PT(n)=rand(1,n) by a matrix M(mxn) but want to have a different random vector for each column multiplication. Is it possible in Matlab?

E.g. PT=rand(1,4);

`PT*(1 0 0 0;...
     0 0 0 1;... 
     0 1 0 0;...
     0 0 0 1);

but where PT changes for each column multiplication. The only way I can think of is make PT=rand(4,4)and then take diag(PT*M) but it’s very expensive if my matrix M is large.
Any thoughts?

Cheers

Suplemental
using @Nasser arrayfun code takes 3 times longer than a for loop. I see it’s normal but why the big difference?

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  1. Editorial Team
    Editorial Team
    2026-05-28T02:32:20+00:00Added an answer on May 28, 2026 at 2:32 am

    I am not sure if I understood exactly what you are asking.

    But if you mean you have a matrix of vectors, and you want to multiply another matrix by each one of these vectors then one way is to use arrayfun.

    For example: Here we multiply a 5 by 4 matrix with 3 vectors, each is 4 by 1.

    The result is 3 vectors, each is 5 by 1

    pt = rand(4,3);
    M  = rand(5,4);
    r  = arrayfun(@(i) M*pt(:,i),1:size(pt,2),'UniformOutput',false)
    

    gives

    r = 
    
        [5x1 double]    [5x1 double]    [5x1 double]
    
    cell2mat(r)
    
    ans =
    
        0.1463    0.4386    0.4638
        0.4104    0.8105    0.6455
        0.9503    1.0145    1.0369
        1.3011    1.4583    1.5233
        0.4688    0.7405    0.7492
    
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