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Editorial Team
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Asked: 2026-06-05T20:13:04+00:00

I’d like to retrieve the image source within the below HTML code block, but

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I’d like to retrieve the image source within the below HTML code block, but can’t find the right syntax.

library(XML)
library(RCurl)
script <- getURL("http://www.floraweb.de/pflanzenarten/druck.xsql?suchnr=4346")
(doc <- htmlParse(script))


<div class="divider"><hr></div>
<div id="contentblock"><div id="content">
<h1>Alle Angaben</h1>
<p>Zu der von Ihnen gewählten Pflanzenart liegen folgende Informationen vor:</p>
<p><a href="../glossar.html#bname">Wissenschaftlicher Name</a>: Poa badensis agg. </p>
<p><a href="../glossar.html#bdeu">Deutscher Name</a>: Artengruppe Badener Rispengras</p>
<p><a href="../glossar.html#bfam">Familienzugehörigkeit</a>: Poaceae, Süßgräser</p>
<p><a href="../glossar.html#bsta">Status</a>: keine Angaben </p>
<p class="centeredcontent"><img border="0" src="../bilder/Arten/dummy.tmb.jpg"></p>

Desired result:
“../bilder/Arten/dummy.tmb.jpg”

Any pointers are greatly appreciated!

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1 Answer

  1. Editorial Team

    Try the following:

    script <- getURL("http://www.floraweb.de/pflanzenarten/druck.xsql?suchnr=4346")
doc <- htmlTreeParse(script,useInternalNodes=T)
img<-xpathSApply(doc,'//*/p[@class="centeredcontent"]/img',xmlAttrs)
> img[2]
[1] "../bilder/Arten/dummy.tmb.jpg"

    The use of Internal representation maybe necessary

    EDIT:

    I just looked up htmlParse and its equivalent to htmlTreeParse(useInternalNodes=T)

    @Martin Morgan thanks have added below

    doc <- htmlParse("http://www.floraweb.de/pflanzenarten/druck.xsql?suchnr=4346")
xpathSApply(doc, '//*/p[@class="centeredcontent"]/img/@src')
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