Question

I’d like to take XML in the format below and load each code record into a domain object in my BootStrap.groovy. I want to preserve the formatting of each snippet of code.

XML

<records>     <code>         <language>Groovy</language>         <snippet>             println 'This is Groovy'             println 'A very powerful language'         </snippet>     </code>     <code>         <language>Groovy</language>         <snippet>             3.times {                 println 'hello'             }         </snippet>     </code>     <code>         <language>Perl</language>         <snippet>             @foo = split(',');         </snippet>     </code> </records> 

Domain Object

Code {     String language     String snippet } 

BootStrap.groovy

new Code(language l, snippet: x).save() 

Answer 1

roughly something like this:

def CODE_XML = ''' <records>     <code>         <language>Groovy</language>         <snippet>             println 'This is Groovy'             println 'A very powerful language'         </snippet>     </code>     <code>         <language>Groovy</language>         <snippet>             3.times {                 println 'hello'             }         </snippet>     </code>     <code>         <language>Perl</language>         <snippet>             @foo = split(',');         </snippet>     </code> </records>   ''' def records = new XmlParser().parseText(CODE_XML) records.code.each() { code ->     new Code(language: code.language, snippet: code.snippet).save() }