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Home/ Questions/Q 514833
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:33:57+00:00 2026-05-13T07:33:57+00:00

I’d like to use val to declare multiple variable like this: val a =

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I’d like to use val to declare multiple variable like this:

val a = 1, b = 2, c = 3

But for whatever reason, it’s a syntax error, so I ended up using either:

val a = 1
val b = 2
val c = 3

or

val a = 1; val b = 2; val c = 3;

I personally find both options overly verbose and kind of ugly.

Is there a better option?

Also, I know Scala is very well thought-out language, so why isn’t the val a = 1, b = 2, c = 3 syntax allowed?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:33:57+00:00Added an answer on May 13, 2026 at 7:33 am

    The trivial answer is to declare them as tuples:

    val (a, b, c) = (1, 2, 3)
    

    What might be interesting here is that this is based on pattern matching. What is actually happens is that you are constructing a tuple, and then, through pattern matching, assigning values to a, b and c.

    Let’s consider some other pattern matching examples to explore this a bit further:

    val DatePattern = """(\d{4})-(\d\d)-(\d\d)""".r
    val DatePattern(year, month, day) = "2009-12-30"
    val List(rnd1, rnd2, rnd3) = List.fill(3)(scala.util.Random.nextInt(100))
    val head :: tail = List.range(1, 10)
    
    object ToInt {
      def unapply(s: String) = try {
        Some(s.toInt)
      } catch {
        case _ => None
      }
    }
    
    val DatePattern(ToInt(year), ToInt(month), ToInt(day)) = "2010-01-01"
    

    Just as a side note, the rnd example, in particular, may be written more simply, and without illustrating pattern matching, as shown below.

    val rnd1, rnd2, rnd3 = scala.util.Random.nextInt(100)
    
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