Question

if __name__=='__main__':     parser = OptionParser()     parser.add_option('-i', '--input_file',                      dest='input_filename',                       help='Read input from FILE', metavar='FILE')      (options, args) = parser.parse_args()     print options 

result is

$ python convert.py -i video_* {'input_filename': 'video_1.wmv'} 

there are video_[1-6].wmv in the current folder. Question is why video_* become video_1.wmv. What i’m doing wrong?

Answer 1

Python has nothing to do with this — it’s the shell.

Call

$ python convert.py -i 'video_*' 

and it will pass in that wildcard.

The other six values were passed in as args, not attached to the -i, exactly as if you’d run python convert.py -i video_1 video_2 video_3 video_4 video_5 video_6, and the -i only attaches to the immediate next parameter.

That said, your best bet might to be just read your input filenames from args, rather than using options.input.