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Home/ Questions/Q 6613841
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T20:15:59+00:00 2026-05-25T20:15:59+00:00

if have a problem getting the locale out of a string like: menu_title_en_US menu_title_en

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if have a problem getting the locale out of a string like:

menu_title_en_US
menu_title_en

The locale in this string would be “en_US”. The string that i have to deal with only have alphanumeric characters and underscores. Like variable names in Python.

I have tried the following regex so far:

re.compile(r'_(?P<base_code>[a-z]{2,5})(_(?P<ext_code>[a-z]{2,5})){0,1}$')

which is working fine for strings like “menu_en” and “menu_en_US” but for stings like “menu_title_en” or “menu_title_en_US” it’s not working as expected (extracting en or en_US).

Maybe someone has a quick idea how to solve this Problem.

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  1. Editorial Team
    Editorial Team
    2026-05-25T20:16:00+00:00Added an answer on May 25, 2026 at 8:16 pm

    If you know the locale is always en, en_us, or en_US (stated in a comment), then you don’t need a regex at all:

    locale = the_string[-6:]
    if not locale.startswith('_en_'):
        locale = locale[3:]
    locale = locale[1:]
    

    or

    locale = the_string[-3:]
    for code in '_en', '_en_us', '_en_US':
        if code.endswith(locale):
            break
    else:
        # no locale found
    

    You could add more checks if the data could contain something that looked like a locale but wasn’t — these just check for the underscore plus two characters after.

    However, the regex can be fixed / simplified a bit, too:

    re.compile(r'_(?P<base_code>[a-z]{2})(_(?P<ext_code>[a-zA-z]{2}))?$')
    

    ? is the same as {0,1}, and since the codes are always two characters you want {2] not {2,5}. You want to accept either lower or upper case for the second code.

    It still will have false positives, though.

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