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Home/ Questions/Q 6692067
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T05:49:29+00:00 2026-05-26T05:49:29+00:00

If I call a function, and escape it with a goto, will I be

  • 0

If I call a function, and escape it with a goto, will I be leaking onto the stack? Is that like dividing by zero? Will the universe implode in a reverse-Big-Bang?

This is not my program, but it has almost exactly the same structure…

bool func()
{
    blah(1337.1337);
    uber("iasouhfia");
    if(random) goto escapeLadder;
}

int main(int argc, char* argv[])
{
    for(int i = 0; i < 5000000; i++)
    {
        func();
    } 
    escapeLadder:
    return 0;
}
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  1. Editorial Team
    Editorial Team
    2026-05-26T05:49:29+00:00Added an answer on May 26, 2026 at 5:49 am

    According to draft C++ standard:

    “The scope of a label is the function in which it appears.” (6.1 Labeled statement)

    So, you can’t goto to a label outside the function, hence your question contains a syntax error.

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