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Home/ Questions/Q 5987773
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T22:51:48+00:00 2026-05-22T22:51:48+00:00

If I call myRobot.Speak.sayHi() it always returns undefined . Please, what am I doing

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If I call myRobot.Speak.sayHi() it always returns undefined. Please, what am I doing wrong? Thanks for reply!

var Factory = (function() {

    // Constructor  
    var Robot = function() {

    };

    // Public
    return {
        extendRobot: function(power, methods) {
            Robot.prototype[power] = methods;
        },
        createRobot: function() {
            return new Robot();
        }
    };

}());

Factory.extendRobot('Speak', {
    sayHi: function() {
        return 'Hi, ' + this.name;
    }
});

var myRobot = Factory.createRobot();
myRobot.name = 'Robin';
myRobot.Speak.sayHi() // => ‘Hi, Robin’
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T22:51:49+00:00Added an answer on May 22, 2026 at 10:51 pm
    createRobot: function() {
        var r = new Robot();
        for (var k in r.Speak) {
            if (typeof r.Speak[k] === "function") {
                r.Speak[k] = r.speak[k].bind(r);
            }
        }
        return r;
    }
    

    Rather then returning a new robot, make sure to bind all the methods in your powers to the robot.

    To avoid hard coding in the loops try this:

    Robot.powers = [];
    ...
    extendRobot: function(power, methods) {
        Robot.powers.push(power);
        Robot.prototype[power] = methods;
    },
    createRobot: function() {
        var robot = new Robot();
        Robot.powers.forEach(function(power) {
            for (var method in robot[power]) {
                if (typeof robot[power][method] === "function") {
                    robot[power][method] = robot[power][method].bind(robot);
                }
            }
        });
        return robot;
    }
    

    This relies on Function.prototype.bind so use the ES5 shim or use underscore for supporting old browsers (IE<9)

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