Question

If i create a

char a[100][100];

and send to a function void func(char** a);
It says that a char ()[100] cannot be converted to char *.

I imagined that a char [100][100] is like a pointer to pointer.
Was i wrong?

Thanks

Answer 1

Yes, you were wrong indeed. a char[100][100] is an array of (array of 100 char), and when passing it to a function, it is converted to a pointer to (array of 100 char), a char (*)[100]. The conversion of arrays to pointers when passed as function arguments only affects the outermost level of arrays.

You could either declare the function as taking a parameter of that type,

void func(char (*)[100]);

if you will always pass arrays with 100 columns, or you would have to pass a different argument if you want to keep the function’s type.