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Home/ Questions/Q 1039443
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T15:06:01+00:00 2026-05-16T15:06:01+00:00

If I create a menu with two items (say Item1 and Item2 and then

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If I create a menu with two items (say “Item1” and “Item2” and then create two subitems under each one (1A, 1B, 2A and 2B), and then disable Item1, I’d expect that 1A and 1B wouldn’t show.

And, indeed, if I move onto Item1 they don’t. Unless I then move on to Item2, wait for 2A and 2B to show, and then move back to Item1. At which point 1A and 1B both pop up, fully active.

Is this a known bug? Is it something I can work around? Any suggestions?

The users want to be able to see the things that are currently disabled, or I’d just make things invisible. Sadly, this isn’t an option we can easily use.

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  1. Editorial Team
    Editorial Team
    2026-05-16T15:06:01+00:00Added an answer on May 16, 2026 at 3:06 pm

    I can confirm that this occurs with the MenuStrip for Framework 2.0, 3.5 and 4.0. The only reasonable workaround that I have is to set the Visible property to false, so the item does not appear at all. Not Ideal, but better than having the sub-items accessible.

    Of course you can also create a function that will recursively disable all child items, that way even if they appear, they are at least disabled, you will need to maintain the previous state to ensure that you do not later re-enable a child item that is actually inteded to be disabled etc. The documentation indicates that this is actually what happens, but that is not the case, sub-items remain enabled even when the parent item is disabled.

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