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Home/ Questions/Q 242183
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T20:48:57+00:00 2026-05-11T20:48:57+00:00

If I declare just the 2 varargs methods as follows: public void foo(String… strings)

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If I declare just the 2 varargs methods as follows:

public void foo(String... strings) {
    System.out.println("Foo with Strings");
}

and

public void foo(int... ints) {
    System.out.println("Foo with ints");
}

and then have the code:

foo();

this is a compiler error due to the ambiguity as expected.

However if I have just the following 2 versions of foo:

public void foo(Object... objects) {
    System.out.println("Foo with Objects");
}

and

public void foo(int... ints) {
    System.out.println("Foo with ints");
}

then the code

foo();

calls the ints version of the method. Can anyone explain why the second example isn’t similarly ambiguous and why it resolves to the int method over the Object method. Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T20:48:58+00:00Added an answer on May 11, 2026 at 8:48 pm

    If I recall properly from when I was preparing the scjp, in the first case you have 2 arguments with no relation between them, so the compiler can’t choose one.

    In the second, with boxing enabled (1.5+), int can be Integer which is a subset of Object, and the compiler, in case of conflict, will always use the most specific definition. So Integer (int) is prioritized.

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