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Home/ Questions/Q 7639603
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T08:27:38+00:00 2026-05-31T08:27:38+00:00

If I do something like this: from zipfile import ZipFile zip = ZipFile(archive, a)

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If I do something like this:

from zipfile import ZipFile 

zip = ZipFile(archive, "a")  

for x in range(5):
    zip.writestr("file1.txt", "blabla")

It will create an archive with 5 files all named “file1.txt”. What I want to achieve is having one compressed file to which every loop iteration appends some content. Is it possible without having some kind of auxiliary buffer and how to do this?

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  1. Editorial Team
    Editorial Team
    2026-05-31T08:27:40+00:00Added an answer on May 31, 2026 at 8:27 am

    It’s impossible with zipfile package but writing to compressed files is supported in gzip:

    import gzip
    content = "Lots of content here"
    f = gzip.open('/home/joe/file.txt.gz', 'wb')
    f.write(content)
    f.close()
    
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