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Home/ Questions/Q 5931307
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T14:40:33+00:00 2026-05-22T14:40:33+00:00

If I have a c program, like: SomeTypePtr my_type; my_type = malloc(sizeof(someType)); /* do

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If I have a c program, like:

SomeTypePtr my_type;
my_type = malloc(sizeof(someType));

/* do stuff */

free(my_type);

/* do a bunch of more stuff */

free(my_type);

Does the calling of ‘free’ for my_type do any harm? After I call free(my_type), does the pointer become a null pointer once again?

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  1. Editorial Team
    Editorial Team
    2026-05-22T14:40:34+00:00Added an answer on May 22, 2026 at 2:40 pm

    Deallocating a memory area with free does not make the contents of the pointer NULL. Suppose that you have int *a = malloc (sizeof (int)) and a has 0xdeadbeef and you execute free (a) then after execution a still contains 0xdeadbeef but after the free call this memory address is no more reserved for you. Something like you have rented a flat with malloc used for some time, returned the flat by free then you might have a duplicate key for the flat, but it is not reserved for you.

    Doing a free on an already freed memory will result in double free memory corruption.

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