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Home/ Questions/Q 8987507
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T21:48:41+00:00 2026-06-15T21:48:41+00:00

If I have a class class foo { public: foo() { // spend some

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If I have a class

class foo {
 public:
  foo() { // spend some time and do something. }
 private:
   // some data here
}

Now I have a vector of foo, I want to put this vector into another vector

vector<foo> input; // assume it has 5 elements
vector<foo> output;

Is there ANY performance difference with these two lines?

output.push_back(input[0])
output.emplace_back(input[0])
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  1. Editorial Team
    Editorial Team
    2026-06-15T21:48:42+00:00Added an answer on June 15, 2026 at 9:48 pm

    Is there ANY performance difference with these two lines?

    No, both will initialise the new element using the copy constructor.

    emplace_back can potentially give a benefit when constructing with more (or less) than one argument:

    output.push_back(foo{bar, wibble}); // Constructs and moves a temporary
    output.emplace_back(bar, wibble);   // Initialises directly
    

    The true benefit of emplace is not so much in performance, but in allowing non-copyable (and in some cases non-movable) elements to be created in the container.

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