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Home/ Questions/Q 6920991
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:13:09+00:00 2026-05-27T10:13:09+00:00

If I have a class Foo and a method with the prototype void bar(Foo*

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If I have a class Foo and a method with the prototype void bar(Foo* foo). Is it okay to do: bar(&Foo());?

I know it compiles and works, but since I’m relatively new to C++, I was wondering whether the instance created will be correctly destructed after usage, or if I have to worry about anything else when doing that.

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:13:10+00:00Added an answer on May 27, 2026 at 10:13 am

    That’s not even valid C++. Some compilers may be silly and accept it, but they shouldn’t do it. You cannot take the address of a temporary.

    This restriction is given in section §5.3.1 of the C++ standard:

    The result of the unary & operator is a pointer to its
    operand. The operand shall be an lvalue or a qualified-id.

    Temporaries are prvalues, so they cannot have their address taken.

    Now, assuming your compiler accepts this, the pointer will be valid while the function call runs, but only while it runs. Once it returns the temporary is destroyed, so any pointers to it that still exist (like, if the function stored it) are invalid.

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