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Editorial Team
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Asked: 2026-05-13T08:29:09+00:00

If I have a code like this for(int i=0;i<10;i++) { int iTemp; iTemp =

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If I have a code like this 

for(int i=0;i<10;i++)
{
    int iTemp;
    iTemp = i;
    //.........
}

Does the compiler instantinate iTemp 10 times?

Or it optimize it?

I mean if i rewrite the loop as 

int iTemp;
for(int i=0;i<10;i++)
{
    iTemp = i;
    //.........
}

Will it be faster?

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1 Answer

  1. Editorial Team

    Using reflector you can view the IL generated by the C# compiler.

    .method private hidebysig static void Way1() cil managed
{
    .maxstack 2
    .locals init (
        [0] int32 i)
    L_0000: ldc.i4.0 
    L_0001: stloc.0 
    L_0002: br.s L_0008
    L_0004: ldloc.0 
    L_0005: ldc.i4.1 
    L_0006: add 
    L_0007: stloc.0 
    L_0008: ldloc.0 
    L_0009: ldc.i4.s 10
    L_000b: blt.s L_0004
    L_000d: ret 
}

.method private hidebysig static void Way2() cil managed
{
    .maxstack 2
    .locals init (
        [0] int32 i)
    L_0000: ldc.i4.0 
    L_0001: stloc.0 
    L_0002: br.s L_0008
    L_0004: ldloc.0 
    L_0005: ldc.i4.1 
    L_0006: add 
    L_0007: stloc.0 
    L_0008: ldloc.0 
    L_0009: ldc.i4.s 10
    L_000b: blt.s L_0004
    L_000d: ret 
}

    They’re exactly the same so it makes no performance difference where you declare iTemp.

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