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Home/ Questions/Q 4018264
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T09:57:43+00:00 2026-05-20T09:57:43+00:00

If I have a dict such as: foo = {(‘foo’, 45):5, (‘bar’, 34):3} How

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If I have a dict such as:

foo = {('foo', 45):5, ('bar', 34):3}

How can I check against part of that tuple?

if 'foo' in foo: #should be true
    pass
if 45 in foo: #also should be true

Or some other syntax.

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  1. Editorial Team
    Editorial Team
    2026-05-20T09:57:43+00:00Added an answer on May 20, 2026 at 9:57 am
    >>> foo = {('foo', 45): 5, ('bar', 34): 3}    
    >>> any(t1 == "foo" for (t1, t2) in foo)
    True    
    >>> any(t2 == 45 for (t1, t2) in foo)
    True
    

    If you don’t know where the value is to be found you can just check the whole pair:

    >>> any(45 in pair for pair in foo)
    True
    

    You can also a generators approach (flatten):

    >>> 45 in flatten(foo)
    True
    

    That said, probably the best idea is to build your data so you can check this kind of inclussion in O(1) time (a set? a refactored dictionary?)

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