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Home/ Questions/Q 8585699
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T22:07:54+00:00 2026-06-11T22:07:54+00:00

If I have a global counter and I have two threads that are each

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If I have a global counter and I have two threads that are each incrementing it 100 times in a loop, why is it possible that I can have a value other than 200? I don’t see how accessing the variable is nonatomic.

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  1. Editorial Team
    Editorial Team
    2026-06-11T22:07:55+00:00Added an answer on June 11, 2026 at 10:07 pm

    That is because for most environments, incrementing a memory location is not an atomic operation.

    The sequence of events would be something like

    • The compiler places the value 0 at the memory address 0xABCD
    • Thread 1 reads 0xABCD into a register and increments the register value
    • Thread 1 is interrupted by Thread 2
    • Thread 2 reads the value 0 from the memory address 0xABCD into a register
    • Thread 2 increments the value in the register
    • Thread 2 writes the value from the register to 0xABCD
    • Thread 2 reads the value 1 from 0xABCD, increments the register, and writes back again
    • Thread 1 resumes
    • Thread 1 writes the value from its register, 1, to 0xABCD, overwriting the value 2 that Thread 2 had previously written there.

    To ensure a consistent result, you must make the increment operation atomic. This is often done by placing a thread lock around the increment operation. For example, in C# that might look like

    object mylock = new object();
    ...
    lock (mylock) 
    { 
        myInt++;
    }
    

    Alternatively, in the .NET environment, one could use Interlocked.Increment

    http://msdn.microsoft.com/en-us/library/dd78zt0c.aspx

    Other environments have similar constructs.

    The best reference I have ever come across for threading in the .NET environment (but is a useful read no matter what your environment) is the following

    http://www.albahari.com/threading/

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