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Home/ Questions/Q 7930319
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T20:23:11+00:00 2026-06-03T20:23:11+00:00

If I have a path for a given file, say ‘C:\Folder\OtherFolder\AnotherFolder\file.txt’ , is there

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If I have a path for a given file, say 'C:\Folder\OtherFolder\AnotherFolder\file.txt', is there a way in python I can get all the parent directories for file.txt up to 'OtherFolder'? The depth of the path is not constant, so I can’t just iterate back a certain number of times, but I always need to get up to 'OtherFolder' regardless of depth. I feel like this should be easier than I’m making it, but they say Thursday is the new Monday. 🙂

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  1. Editorial Team
    Editorial Team
    2026-06-03T20:23:12+00:00Added an answer on June 3, 2026 at 8:23 pm

    If you are using Windows, try this:

    import os
    os.path.relpath('C:\Folder\OtherFolder\AnotherFolder\file.txt', 'C:\Folder\OtherFolder')
    

    You can then split it using os.path.sep (in your case \):

    rel_path.split(os.path.sep)
    

    to get the individual directories.

    On a Linux machine a similar call returns what you mean:

    os.path.relpath('/Folder/OtherFolder/AnotherFolder/file.txt', '/Folder/OtherFolder')
    # returns 'AnotherFolder/file.txt'
    
    rel_path.split(os.path.sep)
    # returns ['AnotherFolder', 'file.txt']
    
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