Question

If I have a string like this :

asdasda=1lsdn=sdf=3dfsdf=-sadf= adfgh=1fbfg=fgfg

what is the fastest way to remove a character if 1) it comes after an = and 2) that character is a non alphabet.

In this case the o/p of the function will be :

asdasda=lsdn=sdf=dfsdf=sadf=adfgh=fbfg=fgfg

I am coding in c++.

This is what I have so far

std::string b = "asdasda=1lsdn=sdf=3dfsdf=-sadf= adfgh=1fbfg=fgfg";
int a= 1;
while(a != 0){ 
    a = b.find('=', a);
    a++;
    if(!isalpha(b[a])){
        b.erase(a,1);
    }   
}   
std::cout << b << std::endl;

Answer 1

I am not a c++ developer but how much i know c++ ,i think best solution for your problem is.

std::string s("asdasda=1lsdn=sdf=3dfsdf=-sadf=adfgh=1fbfg=fgfg");
std::string::size_type k = 0;
/*erase character after =*/ 
while((k=s.find('=',k))!=s.npos) {
   s.erase(k+1, 1);
}

/*erase numeric*/
for(i=0;i<=9;i++) {
 std::string::size_type n = 0;
 while((n=s.find(i,n))!=s.npos) {
   s.erase(n, 1);
}

}

There in code may be syntax error , Please check this code before use.

thanks