If I have a struct A defined as:
struct A {
char* c;
float f;
int i;
};
and an array
A col[5];
then why is
sizeof(*(col+0))
16?
If I have a struct A defined as: struct A { char* c; float
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If I have a struct A defined as:
struct A {
char* c;
float f;
int i;
};
and an array
A col[5];
then why is
sizeof(*(col+0))
16?
On your platform, 16 bytes are required to hold that structure, the structure being of type
A.You should keep in mind that
*(col+0)is identical tocol[0]so it’s only one of the structure, not the entire array of them. If you wanted the size of the array, you would usesizeof(col).