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Home/ Questions/Q 234643
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T20:12:05+00:00 2026-05-11T20:12:05+00:00

If I have a union, C standard guarantees that the union itself will be

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If I have a union, C standard guarantees that the union itself will be aligned to the size of the largest element.

union U {
    long l;
    int i;
    short s;
    char c[2];
} u;

But what does it say about alignment of individual union elements inside the union? Is the following expression guaranteed to be true?

(&u.l == &u.i) && (&u.i == &u.s) && (&u.s == &u.c[0])
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  1. Editorial Team
    Editorial Team
    2026-05-11T20:12:05+00:00Added an answer on May 11, 2026 at 8:12 pm

    The start of each element is aligned with the address of the union itself.

    so the individual comparisons in the expression you ask about are true, but the expression as a whole is false unless the union is located at address 0x0001.

    The deleted text applied to the following comparisons:

    &u.l == &u.i == &u.s == &u.c[0]
    

    The revised version compares distinct pointer types – the pointers should be cast to void pointers.


    I was asked to quote the standard – or identify the section of the standard.

    C99 – section 6.7.2.1 Structure and union specifiers (paragraph 14):

    A pointer to a union object, suitably converted, points to each of its members (or if a member is a bitfield, then to the unit in which it resides), and vice versa.

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