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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T11:46:37+00:00 2026-05-13T11:46:37+00:00

If I have an algorithm that takes 4n^2 + 7n moves to accomplish, what

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If I have an algorithm that takes 4n^2 + 7n moves to accomplish, what is its O?
O(4n^2)?
O(n^2)?

I know that 7n is cut off, but I don’t know if I should keep the n^2 coefficient or not.

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-13T11:46:37+00:00Added an answer on May 13, 2026 at 11:46 am

    You should drop any coefficients because the question is really asking “on the order of”, which tries to characterize it as linear, exponential, logarithmic, etc… That is, when n is very large, the coefficient is of little importance.

    This also explains why you drop the +7n, because when n is very large, that term has relatively little significance to the final answer. If you are familiar with calculus, you might say lim n->inf(4*n^2+7n) ~= lim n->inf(4*n^2) ~= lim n->inf(n^2)

    You can also think about this in a graphical sense… that is, if you graph the function 4n^2 + 7n for larger and larger values of n, a mathematician might say “it looks like n^2”. Granted, it would have to be a fairly liberal mathematician, as this isn’t a rigorous statement, but that’s basically what O(…) is trying to convey.

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