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Home/ Questions/Q 905721
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T16:15:57+00:00 2026-05-15T16:15:57+00:00

If I have an array created like this: MyType *array = new MyType[10]; And

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If I have an array created like this:

MyType *array = new MyType[10];

And I want to overwrite one of the elements, do I have to delete first the old element like this:

delete &array[5];
array[5] = *(new MyType());

Or is this completely wrong and do I have to work with something like “pointers to pointers” to fix this job? If so, how please….

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  1. Editorial Team
    Editorial Team
    2026-05-15T16:15:58+00:00Added an answer on May 15, 2026 at 4:15 pm

    It’s an array of values, not of pointers. So you’d just do

    array[5] = MyType();
    

    This requires MyType to support the assignment operator.


    Incidentally, there’s rarely a need for manual array allocation like this in C++. Do away with the new and delete and use std::vector instead:

    std::vector<MyType> array(10);
    array[5] = MyType();
    

    Note, there’s no need to delete anything.

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