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Home/ Questions/Q 3280082
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T19:39:53+00:00 2026-05-17T19:39:53+00:00

If I have an array of strings, such as string[] names = {John Doe,

  • 0

If I have an array of strings, such as

string[] names = {"John Doe", "Doe John", "Another Name", "Name Another"};

How do I sort this array, using insertion sort?

Wikipedia has some examples: https://en.wikibooks.org/wiki/Algorithm_implementation/Sorting/Insertion_sort#C.23

static void InsertSort(IComparable[] array)
{
    int i, j;

    for (i = 1; i < array.Length; i++)
    {
        IComparable value = array[i];
        j = i - 1;
        while ((j >= 0) && (array[j].CompareTo(value) > 0))
        {
            array[j + 1] = array[j];
            j--;
        }
        array[j + 1] = value;
    }
}

and

static void InsertSort<T>(IList<T> list) where T : IComparable<T>
{
    int i, j;

    for (i = 1; i < list.Count; i++)
    {
        T value = list[i];
        j = i - 1;
        while ((j >= 0) && (list[j].CompareTo(value) > 0))
        {
            list[j + 1] = list[j];
            j--;
        }
        list[j + 1] = value;
    }
}

but it doesn’t seem to work on my array of strings, unless I’m doing something wrong.

Would I not run

InsertSort(names); // like so?
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T19:39:53+00:00Added an answer on May 17, 2026 at 7:39 pm

    Works fine for me:

    class Program
    {
        static void Main()
        {
            string[] names = { "John Doe", "Doe John", "Another Name", "Name Another" };
            InsertSort(names);
            foreach (var item in names)
            {
                Console.WriteLine(item);
            }
        }
    
        static void InsertSort(IComparable[] array)
        {
            int i, j;
    
            for (i = 1; i < array.Length; i++)
            {
                IComparable value = array[i];
                j = i - 1;
                while ((j >= 0) && (array[j].CompareTo(value) > 0))
                {
                    array[j + 1] = array[j];
                    j--;
                }
                array[j + 1] = value;
            }
        }
    }
    

    As expected it prints:

    Another Name
    Doe John
    John Doe
    Name Another
    
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