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Home/ Questions/Q 8856665
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T14:24:23+00:00 2026-06-14T14:24:23+00:00

If I have an object containing 20 keys, and over 3000 entries, is there

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If I have an object containing 20 keys, and over 3000 entries, is there a way using d3 to SUM the entire object?

For example if I have:

Country: Germany, val2007:9.3, val2008:8.6
Country: Germany,val2007:3.4, val2008:1.0
Country: Austria, val2007:23.0, val2008:9.2
Country: Austria, val2007:1.2, val2007:3.2

Can I produce an array as the following?

Country: Germany,val2007:12.7, val2008:9.6
Country: Austria, val2007:24.2, val2008:12.4

Bearing in mind that I won’t know the key names all the time and the ‘val’ fields could be anything from val2007 and val2008 to val1997 -> val2017

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  1. Editorial Team
    Editorial Team
    2026-06-14T14:24:24+00:00Added an answer on June 14, 2026 at 2:24 pm

    D3 doesn’t provide a simple way to do this, but it offers several tools that are useful. The first is d3.nest (docs), which can group rows on specific keys. After that, you need to figure out how to sum the rows for, say, Germany yourself – here I use Array#reduce, which I think works well for this sort of problem:

    function rollup(rows) {
        return rows.reduce(function(agg, row) {
            // you could pre-calculate this if all rows had the same keys
            d3.keys(row)
                .filter(function(k) { return k !== 'Country' })
                .forEach(function(k) {
                    if (!(k in agg)) agg[k] = 0;
                    agg[k] += row[k];
                });
            return agg
        }, {});
    }
    
    data = d3.nest()
        .key(function(d) { return d.Country; })
        .rollup(rollup)
        .entries(data)
        .map(function(entry) {
            entry.values.Country = entry.key;
            return entry.values;
        });
    

    You can see the working fiddle here: http://jsfiddle.net/nrabinowitz/MB3yz/

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