Question

If I have at table with, say 10 columns. 8 columns of data and 2 columns (1 and 2) as an identifier.

I would like to calculate “the result” for the 8 columns, for every possible scenario of col1 and col2.

Assume distinct(value) col1 gives {A,B,C} and distinct(value) col2 gives {D,E,F} I would like to sum up the data (any of the 8 columns) GROUP’d BY:

• A,D
• A,E
• A,F
• A,(All of col2)
• B,D
• B,E
• B,F
• B,(All of col2)
• C,D
• C,E
• C,F
• C,(All of col2)
• (All of col1),(All of col2)
• D, (All of col1)
• E, (All of col1)
• F, (All of col1)

Answer 1

SELECT
    SUM(colx) OVER (PARTITION BY Col1)       AS [All of col1],
    SUM(colx) OVER (PARTITION BY Col2)       AS [All of col2],
    SUM(colx) OVER (PARTITION BY Col1, Col2) AS [PerCol1Col2Pair],
    SUM(colx) OVER ()                        AS [All of col1 and All of col2]
FROM
    MyTable