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Home/ Questions/Q 8137533
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T11:09:37+00:00 2026-06-06T11:09:37+00:00

If I have : <div id=mydiv onmouseover=myfunc()> <div id=mydiv1></div> <div id=mydiv2></div> </div> <script> function

  • 0

If I have :

<div id="mydiv" onmouseover="myfunc()">
  <div id="mydiv1"></div>
  <div id="mydiv2"></div>
</div>

<script>
  function myfunc() {
    var evt = window.event || arguments.callee.caller.arguments[0];
    var em = evt.target || evt.srcElement;
    return em.id;
  }
</script>

The function is called by mydiv onmouseover, but if mouse cursor is over mydiv1 function returns mydiv1.

How to make it always to show mydiv?

P.S : I know that I can use something like myfunc(this), but I would like to find caller from inside my function.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T11:09:39+00:00Added an answer on June 6, 2026 at 11:09 am

    Personally I would prefer to use jQuery to hook up the event:

    $('#mydiv').on('mouseover',function(){
        var id = $(this).attr('id');
        // ...
    });
    

    If this should be applied to several elements, then use a class selector instead:

    $('.hoverable').on('mouseover',function(){
        var id = $(this).attr('id');
        // ...
    });
    

    To also handle future content, attach the event handler to a common ancestor, and select the hoverable elements in the second parameter to on:

    $('body').on('mouseover','.hoverable',function(){
        var id = $(this).attr('id');
        // ...
    });
    

    See it in action with future content here.

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