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Home/ Questions/Q 4113126
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T22:17:02+00:00 2026-05-20T22:17:02+00:00

If I have elements with classnames like this: .ses_0 .ses_1 .ses_2 .ses_3 How can

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If I have elements with classnames like this:

   .ses_0 .ses_1 .ses_2 .ses_3  

How can I select all the elements and prepend those with some snippet?
Something like this:

    var sessions = $('*[class*=ses_]');

    for (var i = 0; i < sessions.length; i++)
    {
        sessions [i].prepend("<img src='/Content/img/caticon"+i+".png' />");
    }

That doesn’t work of course.

Edit: Ahhhh… damn It seems that I need to get not only those classes that start with .ses_ but also <a> elements within. How can I do that?

Basically something that works $(".ses_0 a") , only I need to get all the classes start with ses_

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  1. Editorial Team
    Editorial Team
    2026-05-20T22:17:02+00:00Added an answer on May 20, 2026 at 10:17 pm

    You’re almost there:

    // selects all that start with "ses_"
    var sessions = $('[class^="ses_"]');
    

    Even though your loop should work, you could also use the

    sessions.each(function(index){
        this.prepend(... // and so on
    });
    
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