Question

If I have id number and an array in the following format, how do I find out what count (position number) ‘Red’ among all other items where cat == 4? The answer I am looking for #3 of 4.
Array
(
[0] => stdClass Object
(
[id] => 1
[cat] => 1
[que] => Description here.
)

    [1] => stdClass Object
        (
            [id] => 2
            [cat] => 1
            [que] => Description here.
        )

    [2] => stdClass Object
        (
            [id] => 3
            [cat] => 1
            [que] => Description here.
        )
 ....

    [31] => stdClass Object
        (
            [id] => 32
            [cat] => 4
            [que] => Description here.
        )

    [32] => stdClass Object
        (
            [id] => 33
            [cat] => 4
            [que] => Description here.
        )
    [33] => stdClass Object
        (
            [id] => 34
            [cat] => 4
            [que] => Red.
        )

    [34] => stdClass Object
        (
            [id] => 35
            [cat] => 4
            [que] => Description here.
        )
)

Do I need to split array and then loop? Lost…

——— EDIT ———-

OK, I did a bad job explaining…

What I meant was: there are many objects withing this array. They are broken into groups, categories. [cat] is the value for each group. There are multiple items in each group. What I was hoping to get was a number of items in each group and the position of particular item withing that group, for example: 4 out of 12.

Answer 1

$position = 0;
$counts = array();

foreach ($yourarray as $obj) {
    if (!isset($counts[$obj->cat])) $counts[$obj->cat] = 0;
    $counts[$obj->cat]++;
    if ($obj->cat == 4 && $obj->que == "Red") {
        $position = $counts[$obj->cat];
    }
}

if ($position >= 0) {
    echo "Object is $position out of $counts[4] objects in category 4\n";
}
foreach($counts as $key=>$val){
    echo "Category $key has $val objects.\n";
}

(Revised to count all categories)