Question

If I have node.child1.child2, can I use hasattr(node, 'child1.child2') effectively? Will it error if there’s no child1 or simply return false?

Answer 1

hasattr doesn’t take a dotted name like that and navigate down attribute chains. But you can write a function to do it:

def get_deep_attr(obj, attrs):
    for attr in attrs.split("."):
        obj = getattr(obj, attr)
    return obj

def has_deep_attr(obj, attrs):
    try:
        get_deep_attr(obj, attrs)
        return True
    except AttributeError:
        return False