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Home/ Questions/Q 769157
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T18:17:30+00:00 2026-05-14T18:17:30+00:00

If I have the following block of code in a method (using .NET 4

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If I have the following block of code in a method (using .NET 4 and the Task Parallel Library):

var task = new Task(() => DoSomethingLongRunning());
task.Start();

and the method returns, will that task go out of scope and be garbage collected, or will it run to completion? I haven’t noticed any issues with GCing, but want to make sure I’m not setting myself up for a race condition with the GC.

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  1. Editorial Team
    Editorial Team
    2026-05-14T18:17:30+00:00Added an answer on May 14, 2026 at 6:17 pm

    Update:

    After I answered this question (a long time ago!) I found out that it’s not true that Tasks will always run to completion – there’s a small, let’s say “corner” case, where tasks may not finish.

    The reason for that is this: As I have answered previously, Tasks are essentially threads; but they are background threads. Background threads are automatically aborted when all foreground threads finish. So, if you don’t do anything with the task and the program ends, there’s a chance the task won’t complete.

    You should always await on tasks. More information can be found on the excellent answer Jon gave me.


    Original:

    Task are scheduled to the ThreadPool, meaning that they are essentially threads¹ (actually, they encapsulate threads).

    From the Thread documentation:

    It is not necessary to retain a
    reference to a Thread object once you
    have started the thread. The thread
    continues to execute until the thread
    procedure is complete.

    So, no, there is no need to retain a reference to it.

    Also, the documentation states that the preferred way to create a Task is to use it’s factory:

    You can also use the StartNew method
    to create and start a task in one
    operation. This is the preferred way
    to create and start tasks if creation
    and scheduling do not have to be
    separated (…)

    Hope it helps.


    ¹ Accordingly to the documentation:

    A task represents an asynchronous
    operation, and in some ways it
    resembles the creation of a new thread
    or ThreadPool work item, but at a
    higher level of abstraction.

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