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Home/ Questions/Q 8493757
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T23:06:34+00:00 2026-06-10T23:06:34+00:00

If I have the following C++ code (for Windows Os): HANDLE hEvent = ::CreateEvent(NULL,

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If I have the following C++ code (for Windows Os):

HANDLE hEvent = ::CreateEvent(NULL, TRUE, FALSE, NULL);
HANDLE hMutex = ::CreateMutex(NULL, FALSE, NULL);

HANDLE hHandles[] = {
    hEvent,
    hMutex
};

DWORD dwR = ::WaitForMultipleObjects(2, hHandles, FALSE, INFINITE) - WAIT_OBJECT_0;

//if dwR == 0, what state is hMutex in?
//Or, do I need to call ReleaseMutex(hMutex) in that case?

I’m not sure how to handle this situation regarding the mutex.

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  1. Editorial Team
    Editorial Team
    2026-06-10T23:06:36+00:00Added an answer on June 10, 2026 at 11:06 pm

    dwR is not quite zero, it is WAIT_OBJECT_0 + 0, that is your wait was satisfied on the first provided handle. This is event’s handle, so you don’t need to touch your mutex.

    If result is WAIT_OBJECT_0 + 1 then it was mutex handle used to succeed in waiting. And once you are done with things you need to do, you release the ownership by calling ReleaseMutex.

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