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Home/ Questions/Q 6581175
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T16:07:10+00:00 2026-05-25T16:07:10+00:00

If i have the following: class PayBand(models.Model): name = models.CharField(max_length=2) lower_limit = models.IntegerField() upper_limit

  • 0

If i have the following:

class PayBand(models.Model):
    name = models.CharField(max_length=2)
    lower_limit = models.IntegerField()
    upper_limit = models.IntegerField()
    def __str__(self):
        return "%s (%s - %s)" % (self.name, self.lower_limit, self.upper_limit)
    def __unicode__(self):
        return u'%s (%s - %s)' % (self.name, self.lower_limit, self.upper_limit)

How would i return a ‘£’ ?

I assumed it would be:

    def __str__(self):
        return "%s (£%s - £%s)" % (self.name, self.lower_limit, self.upper_limit)

But that didnt work (obviously!), so i tried:

    def __str__(self):
        return "%s (£%s - £%s)" % (self.name, self.lower_limit, self.upper_limit)

But that didn’t work, it just outputted £…

Soooo… my question is how do I output a ‘£’ sign as well as the field?

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  1. Editorial Team
    Editorial Team
    2026-05-25T16:07:10+00:00Added an answer on May 25, 2026 at 4:07 pm

    It’s difficult to answer this well, without seeing how those different methods didn’t work, and knowing what you mean by ‘output’ – do you mean in a template? But here’s a couple of possible ways this could have gone wrong.

    1. When you tried £, did it get escaped? If so, you might need to run mark_safe on the string (assuming it is safe!), or use the |safe filter in your template.
    2. You could try returning a unicode string, with the escaped version of £ in it – that’s u'\xa3'.
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