Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
If I have the strings “hello8459” and “1234”, how would I go about detecting which one had the alphabetical characters in? I’ve been trying:
//Checking for numerics in an if...
Pattern.matches("0-9", string1);
However it doesn’t work at all. Can anyone advise?
“0-9” matches just that, the string: “0-9”.
What you probably meant to do is “[0-9]+” which matches one ore more digits.
And you can use String’s matches(…) method:
Be careful though, when parsing to a primitive int or long after checking ‘onlyDigits’: it might be a large number like 123145465124657897456421345487454 which does not fit in a primitive data type but passes the matches(…) test!