Question

If I have these 2 constructors for MyClass:

MyClass(int n1);
MyClass(int n1, int n2);

and an overloaded (non-member) operator+:

MyClass operator+(MyClass m1, const MyClass& m2);

This enables me to write code like this:

MyClass m;
5 + m:

which I guess uses an implicit cast through the defined constructor, correct?

Is there any way to do this implicit cast with the constructor taking 2 arguments? With code looking something like this:

MyClass m;
{15, 8} + m:

?

Or maybe just do an explicit cast from {9, 4} to a MyClass object?

Answer 1

In a word, no. The most succinct option is MyClass(15,8) + m;.