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Home/ Questions/Q 7757969
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T13:14:04+00:00 2026-06-01T13:14:04+00:00

If I have this code: <div class=lists> <a href=#new_list>New list</a> </div> AND $.ajax({ url:

  • 0

If I have this code:

<div class="lists">
     <a href="#new_list">New list</a>
</div>

AND

 $.ajax({
     url: 'xxx.php',
     type: 'POST',
     data: {
         id_user:<?php echo $id;?>
     },
     dataType: 'html',
     success: function (data) {
         $(".lists").html(data); //here
     }
 }); 

It is possible ignore the .lists>a when replace the content? What i mean is: add the new content data but also keep the original .lists>a

thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T13:14:06+00:00Added an answer on June 1, 2026 at 1:14 pm

    Take a backup of a inside lists and append/prepend them later,

    var $a = $(".lists a").clone();
    $(".lists").html(data).append($a);
    

    Use .prepend insted of .append if you want the links to be above the data html

    Note:

    1. Assuming that the a tags are always in the top/bottom of the .lists.
    2. You have lot of other elements inside .lists which you want to replace with data
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