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Home/ Questions/Q 7048571
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T02:54:29+00:00 2026-05-28T02:54:29+00:00

If I have this index: if (isset($_GET[‘se’])) { $se= $_GET[‘se’]; if (file_exists({$se}.php)){ require({$se}.php); }

  • 0

If I have this index:

if (isset($_GET['se'])) {
    $se= $_GET['se'];

    if (file_exists("{$se}.php")){
        require("{$se}.php");
    }
    else {
        require("page_error.php");
    }
}
else {
    require("page_error.php");
}

A link like the following doesn’t work:

$pwrurl = "http://example.com/login/?se=change_password?usermail=".$email."&usercode=".$linkHash;

Only something like: http://example.com/login/?se=change_password will be accepted.

Can this be solved?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T02:54:29+00:00Added an answer on May 28, 2026 at 2:54 am

    Beware!

    Letting the user decide which file to include without any validation will introduce a vulnerability to your server. They could point your script to any sensitive file.

    You should limit the possibilities of what can be included, like this:

    $allowed_files = array(
        "page_error",
        "some_section",
        "some_other_section",
        "change_password"
        );
    
    $se = empty($_GET['se']) ? "page_error" : $_GET['se'] ; // "page_error" by default.
    
    if (in_array($se, $allowed_files)){
        require("{$se}.php");
    } else {
        require("page_error.php");
    }
    

    This way they can only read the files you put in the array.

    Edit: Also, just like everyone else said, you should separate different param=argument pairs in the URL with & instead of ?. The ? is used to separate the page name from the argument list.

    http://example.com/login/?se=change_password&usermail=...
    
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