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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T16:30:23+00:00 2026-05-12T16:30:23+00:00

If i have this Query: SELECT tableA.Id, tableB.Id FROM tableA JOIN tableB ON (tableA.bId

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If i have this Query:

SELECT tableA.Id, tableB.Id FROM tableA JOIN tableB ON (tableA.bId = tableB.Id)

Now if i try this in php i have some problems:

while($result = mysql_fetch_array(mysql_query(/Query Above/)){
    print $result['tableB.Id'];
}

Now i know what you are going to say that i should do my query as:

SELECT tableA.Id AS aId, tableB.Id AS bId 
FROM tableA 
JOIN tableB ON (tableA.bId = tableB.Id)

and then use: $result['bId']

But the fact is the query is actually like this:

SELECT tableA.*, tableB.* FROM tableA JOIN tableB ON (tableA.bId = tableB.Id)

Is there any way i can get the result in PHP without doing the AS for each individual matching row?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-12T16:30:23+00:00Added an answer on May 12, 2026 at 4:30 pm

    You can’t, per the PHP manual:

    “If two or more columns of the result have the same field names, the last column will take precedence. To access the other column(s) of the same name, you either need to access the result with numeric indices by using mysql_fetch_row() or add alias names.”

    cf. http://www.php.net/manual/en/function.mysql-fetch-assoc.php

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